求n(n=3)个学生的最高分和最低分及姓名，已有student类声明和main函数，完成student类的实现部分。

#include <iostream.h>

#include <string.h>

class student

{char name［10］;

int deg;

public:

student(char na［］="",int d=0);

char * getname();

friend int compare(student &s1,student &s2);

int getdeg();

};

void main()

{student st［］={student("王强",74),student("李刚",68),student("张雪",84)};

int i=0,min=0,max=0;

for(i=1;i<3;i++)

{if(compare(st［max］,st［i］)==-1)

max=i;

if(compare(st［min］,st［i］)==1)

min=i;

}

cout<<"最高分："<<st［max］.getdeg()<<"姓名:"<<st［max］.getname()<<endl;

cout<<"最低分:"<<(*(st+min)).getdeg()<<"姓名:"<<st［max］.getname()<<endl;

}

答案：student::student(char na［］,int d)

{strcpy(name,na);

deg=d;

}

char * student::getname(){return name;}

int compare(student &s1,student &s2)

{if(s1.deg>s2.deg)

return 1;

else if(s1.deg==s2.deg)

return 0;

else return -1;

}

int student::getdeg()

{return deg;}__